LeetCode Problem #11 Container With Most Water

Given n non-negative integers a1, a2, ..., an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container and n is at least 2.

The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.

Problem Link

Solution Number One O(n^2) Brute Force :

Try all valid combinations
outer loop start from i = 0 to length of array
inner loop start from j = i+1 to length of array
compare current area with new area and choose max.
return max area.

Solution Number Two O(n) :

Linear Solution greedy algorithm:

calculating area it is rectangle

width = rightIndex - leftIndex
height = min (height[rightIndex], height[leftIndex])

select max area
update leftIndex and rightIndex

if height[rightIndex] > height[leftIndex] this means we should search for another left leftIndex++
else we need to search for another right rightIndex--

return max area

Thank you,
AhmedG.

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